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\frac{da(t)}{dt} +[\frac{1}{\tau_{act}}·(\beta+(1-\beta)u(t))] · a(t) = \frac{u(t)}{\tau_{act}} |
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| Mathblock |
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\frac{da(t)}{dt} +[\frac{1}{\tau_{act}}·(\beta+(1-\beta)u(t))] · a(t) = \frac{u(t)}{\tau_{act}} |
| Expand | ||
|---|---|---|
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